Periods of Hecke Characters by Norbert Schappacher

By Norbert Schappacher

The place to begin of this Lecture Notes quantity is Deligne's theorem approximately absolute Hodge cycles on abelian kinds. Its functions to the speculation of causes with advanced multiplication are systematically reviewed. particularly, algebraic family among values of the gamma functionality, the so-called formulation of Chowla and Selberg and its generalization and Shimura's monomial family between classes of CM abelian types are all provided in a unified approach, specifically because the analytic reflections of mathematics identities beetween Hecke characters, with gamma values equivalent to Jacobi sums. The final bankruptcy includes a detailed case during which Deligne's theorem doesn't apply.

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We may also assume that n == 4 (mod 8) because we can replace r, if necessary, by rEEl r or rEEl r EEl r EEl r. 1 then yields since r* = r and vol (JRn If) = 1. Since {)r is invariant under T, {)r ((TS)T) = -T~{)r(T). From this formula one derives But (TS)3 = 1, which is a contradiction. This proves (i). n Ir) = 1. 1. 5 r = r* and I' and finishes The Eisenstein Series We now consider some further very important examples of modular forms: Definition. Let k E Z, keven, k > 2. The series Gk(T) = L (=,n)E 1} (=,n);t(O,O) 1 (mT + n)k is called the Eisenstein series of index k.

3 + t . 'Y. 18 1 Lattices and Codes Since t . (3 > 0 and t . 'Y > 0, t . (3 < t . Q and t . 'Y < t . Q. Since t . Q was minimal, the elements (3 and 'Y can be written as linear combinations of elements of St with non-negative integer coefficients, and hence Q, too. This contradicts the assumption. 4 a· (3 s:; 0 for Q, (3 ESt, Q f- (3. Proof. Otherwise, Q . (3 = 1 and hence 'Y = Q - (3 E R. Then either 'Y E Rt or -'Y E Rt· In the first case Q = (3 + 'Y would be decomposable, in the latter case (3 = Q + (-'Y) would be decomposable, both being contradictions.

3 we need the following lemma. 18 Let r be an irreducible root lattice, and let (e1, ... , en) be a fundamental system of roots of r. Then the vectors of r* that have inner product 0 or 1 with all positive roots of r (with respect to (e1, ... , en)) form a complete set of coset representatives for r* Ir. Proof. Let y E r*, y =J 0, be a vector with y. 0: equal to 0 or 1 for all positive roots of r. If (3 denotes the highest root of r, then y . (3 = 1, because otherwise y . (3 = 0 which would imply y .

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